In the equation, which is true about the value of x? 3x + 7(x + 1) = 2(6x + 5) β 2x A.No solutionB.One solutionC. Infinite solutionsD.x = 7, x = 10
Accepted Solution
A:
Option A
ANSWER: Β In the equation, 3x+7(x + 1) = 2(6x + 5) -2x ,no solution exists for βxβ
SOLUTION:
Given equation is 3x + 7(x + 1) = 2(6x + 5) β 2x
By multiplying the terms within the bracket, we get
3x + 7x + 7 = (2)6x + (2)5 β 2x
On simplifying the above equation, we get
3x + 7x + 7 = 12x +10 -2x
10x + 7 = 10x + 10
By moving the terms from right side to left side, we get
(10x -10x) + (7 β 10) = 0 Β
0 + (-3) = 0
-3 = 0
[tex]\text { L.H.S } \neq \mathrm{R.H.S}[/tex]Hence the given equation is invalid for any value of x
So, there is no solution, which satisfies the given equation.