Q:

In the equation, which is true about the value of x? 3x + 7(x + 1) = 2(6x + 5) βˆ’ 2x A.No solutionB.One solutionC. Infinite solutionsD.x = 7, x = 10

Accepted Solution

A:
Option A ANSWER: Β In the equation, 3x+7(x + 1) = 2(6x + 5) -2x ,no solution exists for β€œx” SOLUTION: Given equation is 3x + 7(x + 1) = 2(6x + 5) βˆ’ 2x By multiplying the terms within the bracket, we get 3x + 7x + 7 = (2)6x + (2)5 – 2x On simplifying the above equation, we get 3x + 7x + 7 = 12x +10 -2x 10x + 7 = 10x + 10 By moving the terms from right side to left side, we get (10x -10x) + (7 – 10) = 0 Β  0 + (-3) = 0 -3 = 0 [tex]\text { L.H.S } \neq \mathrm{R.H.S}[/tex]Hence the given equation is invalid for any value of x So, there is no solution, which satisfies the given equation.