Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthesis.) and has a slope of StartFraction 3 Over 4 EndFraction.? y – y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis. = y minus StartFraction 3 Over 4 EndFraction equals StartFraction one-third EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = 4(x – )y – 4 = y minus 4 equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus StartFraction one-third EndFraction right-parenthesis.(x – )
Accepted Solution
A:
Answer:[tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex]Step-by-step explanation:we know thatThe equation of the line into point slope form is equal to[tex]y-y1=m(x-x1)[/tex]In this problem we have[tex]point\ (4,\frac{1}{3})[/tex][tex]m=\frac{3}{4}[/tex]substitute the given values[tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex]y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)