How much pure acid should be mixed with 4 gallons of a 50% acid solution in order to get a 60% acid solution?

Answer:In this case you have 50% solution, so it is 1/2 pure stuff and 1/2 other stuff.You have 4 gallons, so the include 2 gallons of pure stuff and 2 gallons of other stuff (perhaps water).You need 60% mixture.And you have pure stuff to add.So,x = amount of pure stuff to add50%(4) + 100%(x) = 60%(4+x)Notice the final volume is 4+x..5(4) + 1(x) = .6(4) + .6(x)multiply by 10 to eliminate decimals5(4) + 10x = 6(4) + 6(x)20 + 10x = 24 + 6x4x = 4x = 1This suggests you add 1 gallon of pure stuff to 4 gallons of 50% mixture to end up with 5 gallons of 60% mixture.Always check your solution.5 * 60% = 3 gallons of pure stuff and 2 gallons of water.4 * 50% = 2 gallons of pure stuff1 * 100% = 1 gallon of pure stuff.Correct!Answer: Add 1 gallon of pure stuff..Step-by-step explanation: